digression. apparently I needed to prove to myself that I could implement Celsius <-> Fahrenheit conversion in C. derp.
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math-replay/.gitignore
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math-replay/.gitignore
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@ -2,3 +2,4 @@
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*.log
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*.pdf
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*.html
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temperatures
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@ -1,5 +1,8 @@
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CFLAGS += -g -Wall -Wextra
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ALL := $(patsubst %.haml,%.html,$(shell find . -name '*.haml'))
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ALL += $(patsubst %.tex,%.pdf,$(shell find . -name '*.tex'))
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ALL += temperatures
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%.html:%.haml
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47
math-replay/temperatures.c
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math-replay/temperatures.c
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#include <stdio.h>
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#include <stdlib.h>
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#include <string.h>
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double c2f(double celsius) {
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return ((9.0 / 5.0) * celsius) + 32.0;
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}
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double f2c(double fahrenheit) {
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return (5.0 / 9.0) * (fahrenheit - 32.0);
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}
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int die_usage(const char *msg) {
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printf("Usage: temperatures [FC]<temp>\n");
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printf("%s\n", msg);
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exit(1);
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}
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int main(int argc, char * argv[]) {
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if (argc < 2) {
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die_usage("");
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}
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char msg[255];
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double temp;
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const char * temp_string = argv[1];
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size_t temp_len = strlen(temp_string);
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if (strncmp(temp_string, "F", temp_len) > -1) {
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sscanf(temp_string, "F%lf", &temp);
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printf("%.2lf\n", f2c(temp));
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} else if (strncmp(temp_string, "C", temp_len) > -1) {
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sscanf(temp_string, "C%lf", &temp);
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printf("%.2lf\n", c2f(temp));
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} else {
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sprintf(msg, "Argument '%s' does not match '[FC]<temp>'",
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temp_string);
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die_usage(msg);
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}
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return 0;
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}
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