129 lines
3.1 KiB
Plaintext
129 lines
3.1 KiB
Plaintext
%html
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%head
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%title Linear Equations 2
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%script{:type => "text/x-mathjax-config"}
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MathJax.Hub.Config({tex2jax: {inlineMath: [['$','$'], ['\\(','\\)']]}});
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%script{:type => "text/javascript", :src => "http://cdn.mathjax.org/mathjax/latest/MathJax.js?config=TeX-AMS-MML_HTMLorMML"}
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%link{:rel => 'stylesheet', :type => 'text/css', :href => './style.css'}
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%body
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%h2 Solve for $x$:
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#solve-for-x-01.solution
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:escaped
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$$
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\begin{eqnarray}
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6x + 8 & = & 5 \\
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-8 + 6x + 8 & = & 5 - 8 \\
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6x & = & 5 - 8 \\
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6x & = & -3 \\
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6x \times \frac{1}{6} & = & -3 \times \frac{1}{6} \\
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x & = & -3 \times \frac{1}{6} \\
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x & = & -3 \over 6 \\
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x & = & \frac{-1}{2} \\
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\end{eqnarray}
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$$
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%h2 Solve for $x$ (again):
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#solve-for-x-02.solution
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:escaped
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$$
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\begin{eqnarray}
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10x - 2 & = & 8 \\
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10x - 2 + 2 & = & 8 + 2 \\
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10x & = & 10 \\
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10x \over 10 & = & 10 \over 10 \\
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x & = & 10 \over 10 \\
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x & = & 1 \\
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\end{eqnarray}
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$$
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%h2 Solve for $x$ (again):
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#solve-for-x-03.solution
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:escaped
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$$
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\begin{eqnarray}
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6x - 4 & = & 3 \\
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6x - 4 + 4 & = & 3 + 4 \\
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6x & = & 7 \\
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6x \over 6 & = & 7 \over 6 \\
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x & = & 7 \over 6 \\
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\end{eqnarray}
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$$
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%h2 Solve for $x$ (again):
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#solve-for-x-04.solution
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:escaped
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$$
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\begin{eqnarray}
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10x + 7 & = & 8 \\
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10x + 7 - 7 & = & 8 - 7 \\
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10x & = & 1 \\
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10x \over 10 & = & 1 \over 10 \\
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x & = & 1 \over 10 \\
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\end{eqnarray}
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$$
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%h2 Solve for $x$ (again):
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#solve-for-x-05.solution
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:escaped
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$$
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\begin{eqnarray}
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10x + 3 & = & 5 \\
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10x + 3 - 3 & = & 5 - 3 \\
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10x & = & 2 \\
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10x \over 10 & = & 2 \over 10 \\
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x & = & 1 \over 5 \\
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\end{eqnarray}
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$$
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%h2 Solve for $x$ (again):
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#solve-for-x-06.solution
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:escaped
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$$
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\begin{eqnarray}
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4x + 9 & = & 10 \\
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4x + 9 - 9 & = & 10 - 9 \\
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4x & = & 1 \\
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4x \over 4 & = & 1 \over 4 \\
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x & = & 1 \over 4 \\
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\end{eqnarray}
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$$
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%h2 Solve for $x$ (again):
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#solve-for-x-07.solution
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:escaped
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$$
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\begin{eqnarray}
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7x - 5 & = & 9 \\
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7x - 5 + 5 & = & 9 + 5 \\
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7x & = & 14 \\
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7x \over 7 & = & 14 \over 7 \\
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x & = & 2 \\
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\end{eqnarray}
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$$
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%h2 Solve for $x$ (again):
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#solve-for-x-08.solution
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:escaped
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$$
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\begin{eqnarray}
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3x + 9 & = & 9 \\
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3x + 9 - 9 & = & 9 - 9 \\
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3x & = & 0 \\
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3x \over 3 & = & 0 \over 3 \\
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x & = & 0 \\
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\end{eqnarray}
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$$
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%h2 Solve for $x$ (again):
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#solve-for-x-09.solution
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:escaped
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$$
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\begin{eqnarray}
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3x + 10 & = & 7 \\
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3x + 10 - 10 & = & 7 - 10 \\
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3x & = & -3 \\
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3x \over 3 & = & -3 \over 3 \\
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x & = & -1 \\
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\end{eqnarray}
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$$
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