printing members of argv with pointer arithmetic

ex15.c

@@ -49,5 +49,13 @@ int main(int argc, char *argv[])
                 *cur_name, *cur_age);
     }
 
+    printf("---\n");
+
+    char **arg = argv;
+    for(i = 0; i < argc; i++) {
+        printf("argument %d is '%s'\n", i, *arg);
+        arg++;
+    }
+
     return 0;
 }