solved some algebra equations

cat-town
Dan Buch 13 years ago
parent 952ad44844
commit 18b6b315f0

@ -0,0 +1,68 @@
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%title New Definitions 1
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%h2 $x `not` $y = 8x - 3y$:
.solution
:escaped
$$
\begin{eqnarray}
x `not` y & = & 8x - 3y \\
6 `not` -2 & = & 8(6) - 3(-2) \\
6 `not` -2 & = & 48 + 6 \\
6 `not` -2 & = & 54 \\
\end{eqnarray}
$$
%h2 $x `star` y = 8y + 2$:
.solution
:escaped
$$
\begin{eqnarray}
x `star` y = 8y + 2 \\
-2 `star` 5 = 8(5) + 2 \\
-2 `star` 5 = 40 + 2 \\
-2 `star` 5 = 42 \\
\end{eqnarray}
$$
%h2 $x `diamond` y = xy + 3x - y$:
.solution
:escaped
$$
\begin{eqnarray}
x `diamond` y = xy + 3x - y \\
3 `diamond` -2 = (3)(-2) + 3(3) - (-2) \\
3 `diamond` -2 = -6 + 9 + 2 \\
3 `diamond` -2 = -6 + 11 \\
3 `diamond` -2 = 5 \\
\end{eqnarray}
$$
%h2 $x `not` y = x + 3y$:
.solution
:escaped
$$
\begin{eqnarray}
x `not` y = x + 3y \\
-4 `not` 6 = -4 + 3(6) \\
-4 `not` 6 = -4 + 18 \\
-4 `not` 6 = 14 \\
\end{eqnarray}
$$
%h2 $x `donut` y = 3x - 3y$:
.solution
:escaped
$$
\begin{eqnarray}
x `donut` y = 3x - 3y \\
0 `donut` 0 = 3(0) - 3(0) \\
0 `donut` 0 = 0 - 0 \\
0 `donut` 0 = 0 \\
\end{eqnarray}
$$
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