box-o-sand/math-replay/algebra/linear-equations-2.haml

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%head
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%title Linear Equations 2
%script{:type => "text/x-mathjax-config"}
MathJax.Hub.Config({tex2jax: {inlineMath: [['$','$'], ['\\(','\\)']]}});
%script{:type => "text/javascript", :src => "http://cdn.mathjax.org/mathjax/latest/MathJax.js?config=TeX-AMS-MML_HTMLorMML"}
2012-04-04 02:25:46 +00:00
%link{:rel => 'stylesheet', :type => 'text/css', :href => './style.css'}
%body
%h2 Solve for $x$:
#solve-for-x-01.solution
:escaped
$$
\begin{eqnarray}
6x + 8 & = & 5 \\
-8 + 6x + 8 & = & 5 - 8 \\
6x & = & 5 - 8 \\
6x & = & -3 \\
6x \times \frac{1}{6} & = & -3 \times \frac{1}{6} \\
x & = & -3 \times \frac{1}{6} \\
x & = & -3 \over 6 \\
x & = & \frac{-1}{2} \\
\end{eqnarray}
$$
2012-04-03 20:45:29 +00:00
%h2 Solve for $x$ (again):
#solve-for-x-02.solution
:escaped
$$
\begin{eqnarray}
10x - 2 & = & 8 \\
10x - 2 + 2 & = & 8 + 2 \\
10x & = & 10 \\
10x \over 10 & = & 10 \over 10 \\
x & = & 10 \over 10 \\
x & = & 1 \\
\end{eqnarray}
$$
%h2 Solve for $x$ (again):
#solve-for-x-03.solution
:escaped
$$
\begin{eqnarray}
6x - 4 & = & 3 \\
6x - 4 + 4 & = & 3 + 4 \\
6x & = & 7 \\
6x \over 6 & = & 7 \over 6 \\
x & = & 7 \over 6 \\
\end{eqnarray}
$$
2012-04-04 01:52:19 +00:00
%h2 Solve for $x$ (again):
#solve-for-x-04.solution
:escaped
$$
\begin{eqnarray}
10x + 7 & = & 8 \\
10x + 7 - 7 & = & 8 - 7 \\
10x & = & 1 \\
10x \over 10 & = & 1 \over 10 \\
x & = & 1 \over 10 \\
\end{eqnarray}
$$
%h2 Solve for $x$ (again):
#solve-for-x-05.solution
:escaped
$$
\begin{eqnarray}
10x + 3 & = & 5 \\
10x + 3 - 3 & = & 5 - 3 \\
10x & = & 2 \\
10x \over 10 & = & 2 \over 10 \\
x & = & 1 \over 5 \\
\end{eqnarray}
$$
%h2 Solve for $x$ (again):
#solve-for-x-06.solution
:escaped
$$
\begin{eqnarray}
4x + 9 & = & 10 \\
4x + 9 - 9 & = & 10 - 9 \\
4x & = & 1 \\
4x \over 4 & = & 1 \over 4 \\
x & = & 1 \over 4 \\
\end{eqnarray}
$$
%h2 Solve for $x$ (again):
#solve-for-x-07.solution
:escaped
$$
\begin{eqnarray}
7x - 5 & = & 9 \\
7x - 5 + 5 & = & 9 + 5 \\
7x & = & 14 \\
7x \over 7 & = & 14 \over 7 \\
x & = & 2 \\
\end{eqnarray}
$$
%h2 Solve for $x$ (again):
#solve-for-x-08.solution
:escaped
$$
\begin{eqnarray}
3x + 9 & = & 9 \\
3x + 9 - 9 & = & 9 - 9 \\
3x & = & 0 \\
3x \over 3 & = & 0 \over 3 \\
x & = & 0 \\
\end{eqnarray}
$$
%h2 Solve for $x$ (again):
#solve-for-x-09.solution
:escaped
$$
\begin{eqnarray}
3x + 10 & = & 7 \\
3x + 10 - 10 & = & 7 - 10 \\
3x & = & -3 \\
3x \over 3 & = & -3 \over 3 \\
x & = & -1 \\
\end{eqnarray}
$$